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3x^2+32x^2+61x-24=0
We add all the numbers together, and all the variables
35x^2+61x-24=0
a = 35; b = 61; c = -24;
Δ = b2-4ac
Δ = 612-4·35·(-24)
Δ = 7081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{7081}}{2*35}=\frac{-61-\sqrt{7081}}{70} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{7081}}{2*35}=\frac{-61+\sqrt{7081}}{70} $
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